Join() Takes Exactly One Argument (2 Given) August 21, 2024 Post a Comment I'm getting error with this code: Traceback (most recent call last): File './main.py', line 172, in grab_first_name f_name = ''.join(n.split()[0], '\n') TypeError: join() takSolution 1: Probably you meant this:'\n'.join(n.split()[0]) CopySolution 2: Did you mean to say: f_name = n.split()[0] + '\n'CopyBaca JugaIs There A Way To Get Your Email Address After Authenticating With Gmail Using Oauth?Importerror: No Module Named Pytqt5Pypyodbc - Invalid Cursor State When Executing Stored Procedure In A Loop Share You may like these postsPython Gmail Api Won't Pass Labelids Parameter To List MethodRunning Opencv From A Python VirtualenvMatplotlib Latex In Legend Label Vs In Axis LabelHow Do I Create An Exception To A Group Action In Click Post a Comment for "Join() Takes Exactly One Argument (2 Given)"
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