Parsing Huge, Badly Encoded Xml Files In Python
Solution 1:
If the problems are actual character encoding problems, rather than malformed XML, the easiest, and probably most efficient, solution is to deal with it at the file reading point. Like this:
import codecs
from lxml importetreeevents= ("start", "end")
reader = codecs.EncodedFile(xmlfile, 'utf8', 'utf8', 'replace')
context = etree.iterparse(reader, events=events)
This will cause the non-UTF8-readable bytes to be replaced by '?'. There are a few other options; see the documentation for the codecs module for more.
Solution 2:
Since the problem is being caused by illegal XML characters, in this case the 0x19 byte, I decided to strip them off. I found the following regular expression on this site:
invalid_xml = re.compile(u'[\x00-\x08\x0B-\x0C\x0E-\x1F\x7F]')
And I wrote this piece of code that removes illegal bytes while saving an xml feed:
conn = urllib2.urlopen(xmlfeed)
xmlfile = open('output', 'w')
while True:
data = conn.read(4096)
ifdata:
newdata, count = invalid_xml.subn('', data)
if count > 0 :
print 'Removed %s illegal characters from XML feed' % count
xmlfile.write(newdata)
else:
break
xmlfile.close()
Solution 3:
I used a similar piece of code:
illegalxml = re.compile(u'[\x00-\x08\x0b\x0c\x0e-\x1F\uD800-\uDFFF\uFFFE\uFFFF]')
...
illegalxml.sub("?",mystring)
...
However, this did not work for all possible strings (400+MB string).
For a final solution I used decoding/encoding as follows:
outxml = "C:/path_to/xml_output_file.xml"withopen(outxml, "w") asout:
valid_xmlstring = mystring.encode('latin1','xmlcharrefreplace').decode('utf8','xmlcharrefreplace')
out.write(valid_xmlstring)
Solution 4:
I had a similar problem with char "" in my xml file, which is also invalid xmlchar. This is because in the xml version 1.0, the characters like �,  are not allowed. And the rule is that all character composition as regular expression '&#x[0-1]?[0-9A-E]' are not allowed. My purpose it to correct the invalid char in a huge xml file, based on Rik's answer, I improved it as below :
import re
invalid_xml = re.compile(r'&#x[0-1]?[0-9a-eA-E];')
new_file = open('new_file.xml','w')
withopen('old_file.xml') as f:
for line in f:
nline, count = invalid_xml.subn('',line)
new_file.write(nline)
new_file.close()
Post a Comment for "Parsing Huge, Badly Encoded Xml Files In Python"