Python Regex Find Values With Newline Character Also

I am working on this regex problem I'm unable to solve. The regex I've made import re message = '''[key X] value [key X] value value [key X] value value value value [key

Solution 1:

You may use

(?m)^\[([^][]*)]\s+(.*(?:\n(?!\[[^][]*]).*)*)

See the regex demo

Details

• ^ - start of a line
• \[ - [
• ([^][]*) - Group 1: any 0+ chars other than [ and ]
• ] - a ] char
• \s+ - 1+ whitespaces
• (.*(?:\n(?!\[[^][]*]).*)*) - Group 2:
  • .* - the rest of the line
  • (?:\n(?!\[[^][]*]).*)* - zero or more repetitions of:
    • \n(?!\[[^][]*]) - a newline not followed with a [...] substring
    • .* - the rest of the line

Python demo:

import re
message = """[key    X] value
[key    X]  value value
[key    X]  value
value
value
value
[key     ] value
[key     ] ?
[key     ] ?"""

messageRegex = re.compile(r"^\[([^][]*)]\s+(.*(?:\n(?!\[[^][]*]).*)*)", re.M)

for value in messageRegex.findall(message):
    print(value)

Output:

('key    X', 'value')
('key    X', 'value value')
('key    X', 'value\nvalue\nvalue\nvalue')
('key     ', 'value')
('key     ', '?')
('key     ', '?')