Python Regex: Create Dictionary From String

I have a sting containing multiple informations which I want to save in a dictionary: s1 = '10:12:01 R1 3 E44' s2 = '11:11:01 R100 E400' pattern = '\d{2}:\d{2}:\d{2}(\

Solution 1:

>>> import re
>>> pattern = "(?P<time>\d{2}:\d{2}:\d{2}(\,\d+)?) +(?P<id1>[0-9A-Za-z_]{2}([0-9A-Za-z1-9_]{1})?([0-9A-Za-z_]{1})?) +(?P<id2>[0-9A-Za-z_]{2}([0-9A-Za-z1-9_]{1})?([0-9A-Za-z_]{1})?$)"
>>>
>>> s1 = "10:12:01    R123    E44">>> print(re.match(pattern, s1).groupdict())
{'time': '10:12:01', 'id1': 'R123', 'id2': 'E44'}

Solution 2:

If the information is cleanly divided by whitespaces, why not use that information to split the string by whitespace and create the resultant list of dictionaries. If we have multiple whitespaces, we can ignore those whitespaces while splitting using re.split

import re

#List of strings
li = [ "10:12:01    R1 3    E44", "11:11:01    R100    E400"]

#List of kyes
keys = ['time', 'id1', 'id2']

#Create the dictionary from keys from keys listand values obtained by splitting string on 2 or more whitespaces
result = [{keys[idx]:re.split(r'\s{2,}', s)[idx] for idx inrange(len(keys))} for s in li]

print(result)

The output will be

[
{'time': '10:12:01', 'id1': 'R1 3', 'id2': 'E44'}, 
{'time': '11:11:01', 'id1': 'R100', 'id2': 'E400'}
]